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Title:

Grade: 10-a Lesson: S2-L3

Explanation:

From the figure we can observe that
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\begin{align} AB ∥ DC \tag{Given}\\ AD ∥ BC \tag{Given}\\ \end{align}

Consider \$\triangle ABC\$ and \$\triangle CDA\$

\begin{align} CA &= AC \tag{Common side} \\ AB &= CD \tag{Given} \\ BC &= DA \tag{Given} \\ \end{align}

So, \begin{align} \triangle ABC \cong \triangle CDA \\ \end{align}

Henced proved that \$\triangleABC\$ \$\cong\$ \$\triangleCDA\$ by the SSS congruence rule.

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Steps	Statment	Solution
1	Given	From the figure we can observe that
2	Side of triangles	AB ∥ DC and AD ∥ BC
3	Consider triangles	\$\triangle ABC and \triangle CDA\$
4	Common side	CA = AC
5	Side of triangles	AB = CD and BC = DA
6	So, Congruency	\$\triangle ABC \cong \triangle CDA\$
7	Prove that	Henced proved that \$\triangleABC\$ \$\cong\$ \$\triangleCDA\$ by the SSS congruence rule.

Steps

Statment

Solution

Given

From the figure we can observe that

Side of triangles

AB ∥ DC and AD ∥ BC

Consider triangles

\$\triangle ABC and \triangle CDA\$

Common side

CA = AC

Side of triangles

AB = CD and BC = DA

So, Congruency

\$\triangle ABC \cong \triangle CDA\$

Prove that

Henced proved that \$\triangleABC\$ \$\cong\$ \$\triangleCDA\$ by the SSS congruence rule.