Lesson Example Discussion Quiz: Class Homework |
Step-4 |
Title: Pairs of angles |
Grade: 10-a Lesson: S1-L3 |
Explanation: |
| Step | Type | Explanation | Answer |
|---|---|---|---|
1 |
Problem |
Suppose two angles \$\angle MON\$ and \$\angle PON\$ form linear pair at point O in a line segment MP.If the difference between the two angles is 80°.Then find the both angles. |
|
2 |
Step |
Given |
so given \$\angle MON\$ and \$\angle PON\$ from linear pair |
3 |
Step |
So from equation (1) |
\$\angle MON\$ + \$\angle PON\$ = 180° |
4 |
Step |
And also given equation (2) |
\$\angle MON\$ - \$\angle PON\$ = 80° |
5 |
Step |
Then adding equation (1) and (2) |
\$\angle MON\$ + \$\angle PON\$ + \$\angle MON\$ - \$\angle PON\$ = 180 + 80 |
6 |
Step |
After simplication we get |
2\$\angle MON\$ = 260 |
7 |
Step |
After simplication we get |
\$\angle MON\$ = \$(\cancel(260)^130) /(\cancel(2)^1)\$ |
8 |
Step |
After simplication we get |
\$\angle MON\$ = 130° |
9 |
Step |
Now putting the value of \$\angle MON\$ in equation 1, we get |
\$\angle PON \$ = 180 - \$\angle MON\$ |
10 |
Step |
Now Substitute the value of \$\angle MON\$ |
\$\angle PON \$ = 180 - 130 |
11 |
Step |
After simplication we get |
\$\angle PON \$ = 50° |
12 |
Answer |
\$\angle MON = 130°\$ and \$\angle PON = 50°\$ |
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