Lesson Example Discussion Quiz: Class Homework |
Step-3 |
Title: Pairs of angles |
Grade: 10-a Lesson: S1-L3 |
Explanation: |
| Step | Type | Explanation | Answer |
|---|---|---|---|
1 |
Problem |
What is value of \$\angleCOF\$. |
|
2 |
Step |
Given |
\$\angle AOC = 4x\$ , \$\angle EOD = 5x\$ and \$\angle BOF = 6x\$ |
3 |
Clue |
Vertically oopposite angles |
\$\angle AOC = \angle BOD = 4x\$ |
4 |
Clue |
Vertically oopposite angles |
\$\angle EOD = \angle COF = 5x\$ |
5 |
Clue |
Vertically oopposite angles |
\$\angle BOF = \angle AOE = 6x\$ |
6 |
Step |
Now, sum of all angles around a point is 360° |
\$\angle BOF + \angle AOE + \angle EOD + \angle COF + \angle AOC + \angle BOD = 360° \$ |
7 |
Step |
Now Substitute the values |
6x + 6x + 5x + 5x + 4x + 4x = 360 |
8 |
Step |
After simplication we get |
30 x = 360 |
9 |
Step |
After simplication we get |
x = \$(\cancel(360)^12) /(\cancel(30)^1)\$ |
10 |
Step |
After simplication we get |
x = 12 |
11 |
Step |
Now find the \$\angle COF\$ |
\$\angle COF = 5x\$ |
12 |
Step |
Now Substitute the x value |
\$\angle COF = 5 times 12\$ |
13 |
Step |
Now Substitute the x value |
\$\angle COF = 60°\$ |
14 |
Answer |
The \$\angle COF = 60°\$ |
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