Lesson Example Discussion Quiz: Class Homework |
Step-2 |
Title: Pairs of angles |
Grade: 10-a Lesson: S1-L3 |
Explanation: |
| Step | Type | Explanation | Answer |
|---|---|---|---|
1 |
Problem |
What is the value of x in the given figure. |
|
2 |
Step |
Given |
\$\angle A = 30\$° , \$\angle B = 6k\$ and \$\angle C = 3k\$ and x = ! |
3 |
Step |
In triangle the sum of all angles = 180° |
\$\angle A\$ + \$\angle B\$ + \$\angle C\$ = 180° |
4 |
Step |
Substitute the value \$\angle A\$ + \$\angle B\$ + \$\angle C\$ |
30 + 6k + 3k = 180 |
5 |
Step |
After simplication we get |
9k = 180 -30 |
6 |
Step |
After simplication we get |
9k = 150 |
7 |
Step |
After simplication we get |
k = 16.66° |
8 |
Step |
Now find the value x |
x + \$\angle ACB\$ = 180 |
9 |
Step |
Substitute the value of \$\angle C\$ |
x + 3k = 180 |
10 |
Step |
Now Substitute the value of k |
\$x + 3 times 16.66 = 180\$ |
11 |
Step |
After simplication we get |
x = 180-49.98 |
12 |
Step |
After simplication we get |
x = 130.02° |
13 |
Answer |
The angle x = 130.02° |
|
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