Step-1

Title: Pairs of angles

Grade: 10-a Lesson: S1-L3

Explanation:

Step Type Explanation Answer

1

Problem

Find the values of Angle A and Angle B, if they are supplementary angles such that ∠A = (2x + 20)° and ∠B = (6x - 39)°.

2

Step

Given

The given ∠A = (2x + 20)° and ∠B = (6x - 39)°

3

Step

Set up equation

∠A + ∠B = 180°

4

Step

Substitute the given expressions for ∠A and ∠B into the equation

(2x + 20)° + (6x - 39)° = 180°

5

Step

Simplify the equation

2x + 20 + 6x - 39 = 180

6

Step

Combine like terms

8x - 19 = 180

7

Step

After simplication

8x = 199

8

Step

After simplication

x = 24.875

9

Step

Substitute the value of x back into the expressions for ∠A and ∠B to find their values

∠A = (2x + 20)°
= \$2 times 24.875 + 20\$
= 69.75°

10

Step

Substitute the value of x back into the expressions for ∠A and ∠B to find their values

∠B = (6x - 39)°
= \$6 times 24.875 - 39\$
= 110.25°

11

Answer

So the ∠A = 69.75° and ∠B = 110.25°


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