Lesson Example Discussion Quiz: Class Homework |
Step-2 |
Title: Surface area for Cube & Cylinder |
Grade: 6-a Lesson: S3-L2 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
Step | Type | Explanation | Answer |
---|---|---|---|
1 |
Problem |
The diagonal of a cube is \$\sqrt 75 "cm"\$. What is the length of one side of the cube? |
|
2 |
Step |
The given diagonal of a cube is(d) |
\$\sqrt 75 "cm"\$ |
3 |
Formula |
To find the diagonal of a cube(d), you can use the formula: |
\$"d" = "s"\sqrt3\$ |
4 |
Step |
Plug the values into the formula: |
\$\sqrt(75) = "s"\sqrt3\$ |
5 |
Step |
To solve for s, we divide both sides by \$\sqrt3\$ |
⇒ \$"s" = \sqrt(75)/\sqrt(3) \$ |
6 |
Step |
After simplification |
⇒ \$"s" = \sqrt(25)\$ |
7 |
Step |
So,the side length of a cube is 5 cm. |
|
8 |
SumUp |
Can you summarize what you’ve understood in the above steps? |
|
9 |
Choice.A |
This is incorrect because it doesn’t match the calculated value of 5 cm |
5 cm |
10 |
Choice.B |
This is incorrect for the same reason; it doesn’t match the calculated value of 5 cm |
10 cm |
11 |
Choice.C |
This is the correct answer based on the calculations using the Pythagorean theorem for a cube |
21 cm |
12 |
Choice.D |
This is incorrect because it doesn’t correspond to the given units |
30 cm |
13 |
Answer |
Option |
A |
14 |
SumUp |
Can you summarize what you’ve understood in the above steps? |
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