Lesson Example Discussion Quiz: Class Homework |
Step-4 |
Title: Surface area for Cone & Cuboid |
Grade: 6-a Lesson: S3-L1 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
Step | Type | Explanation | Answer |
---|---|---|---|
1 |
Problem |
The slant height of a cone is 17 m. the diameter of the base is 18 m. Find the total surface area of the cone. |
|
2 |
Step |
The given values are |
h = 17 m and d = 18 m |
3 |
Hint |
\$"radius" = ("diameter")/2\$ |
⇒ \$"r" = 18/2\$ |
4 |
Formula |
Now, first calculate the lateral surface area |
\$"lateral surface area" = π"rl"\$ |
5 |
Step |
Plug the values in the formula |
⇒ \$"lateral surface area" = π times 9 times 17\$ |
6 |
Step |
Then calculate the area of base |
\$"Base area" = π("r")^2\$ |
7 |
Step |
Now plug the values in the formula |
⇒ \$"Base area" = π(9)^2\$ |
8 |
Formula |
Calculate the total surface area is |
Total surface area = lateral surface area + base area |
9 |
Step |
Now plug the values in the formula |
Total surface area = 153π + 81π |
10 |
Step |
After simplification |
Total surface area = 234π |
11 |
Step |
So, the total surface area of the cone is 234π sq.m. |
|
12 |
SumUp |
Can you summarize what you’ve understood in the above steps? |
|
13 |
Choice.A |
This is correct because it accurately represents the calculated total surface area of the cone |
234π sq.m |
14 |
Choice.B |
This is incorrect because it does not accurately represents the calculated total surface area of the cone |
243π sq.m |
15 |
Choice.C |
This is incorrect because it does not include the factor of π in the answer |
234 sq.m |
16 |
Choice.D |
This is incorrect because it does not include the factor of π in the answer |
243 sq.m |
17 |
Answer |
Option |
A |
18 |
SumUp |
Can you summarize what you’ve understood in the above steps? |
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