Lesson Example Discussion Quiz: Class Homework |
Step-4 |
Title: Quadrilaterals( Trapezium , Parallelogram) |
Grade: 6-a Lesson: S2-L6 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
Step | Type | Explanation | Answer |
---|---|---|---|
1 |
Problem |
The perimeter of a parallelogram is 72 feet, and its area is 425 square feet. If the length is 19 feet, calculate the height of the parallelogram.(note:take width as a base) |
|
2 |
Step |
The height of the parallelogram with a given length |
19 ft |
3 |
Step |
The perimeter is given as |
72 ft |
4 |
Step |
Perimeter of parallelogram |
P = 2(l + w) |
5 |
Step |
So, find the width (base) |
72 = 2(19 + w) |
6 |
Step |
Divide 2 on both sides |
36 = 19 + w |
7 |
Step |
To find the width, subtract 19 from both sides |
36 - 19 = 19 - 19 + w w = 17 ft |
8 |
Step |
Now that you have the width (base) and the length, you can calculate the height (h) using the given area: |
Area = \$"base" \times "height"\$ 425 = \$17 \times h\$ |
9 |
Step |
To find the height, divide both sides by 17 feet: |
\$427/17\$ = h h = 25 ft |
10 |
Step |
So, the height of the parallelogram is 25 feet when the length is 19 feet, and the width is taken as the base. |
|
11 |
SumUp |
Can you summarize what you’ve understood in the above steps? |
|
12 |
Choice.A |
This is not correct because it doesn’t match the calculated area for the given parallelogran |
23 feet |
13 |
Choice.B |
This is not correct because it doesn’t match the calculated area for the given parallelogran |
24 feet |
14 |
Choice.C |
This is correct because it matches the calculated perimeter for the given parallelogram |
25 feet |
15 |
Choice.D |
This is not correct because it doesn’t match the calculated area for the given parallelogran |
26 feet |
16 |
Answer |
Option |
C |
17 |
SumUp |
Can you summarize what you’ve understood in the above steps? |
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