Lesson Example Discussion Quiz: Class Homework |
Step-3 |
Title: Quadrilaterals (Rhombus, Square) |
Grade: 6-a Lesson: S2-L5 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
Step | Type | Explanation | Answer |
---|---|---|---|
1 |
Problem |
ABCD is a rhombus whose diagonals intersect at O. If AB = 13 cm, diagonal BD = 24 cm, find the length of diagonal AC. |
|
2 |
Step |
We know in rhombus, diagonals bisect each other at the right angle In ΔAOB |
BO = \$(BD)/2\$ = \$24/2\$ = 12 cm |
3 |
Formula |
Using Pythagoras’s theorem in ΔAOB |
\$AB^2 = AO^2 + BO^2\$ |
4 |
Step |
Substitute the value in the formula |
⇒ \$13^2 = AO^2 + 12^2\$ ⇒ \$169 = AO^2 + 144\$ |
5 |
Step |
Now simplify the equation |
⇒ \$AO^2 = 169 - 144\$ ⇒ \$AO^2 = 25\$ |
6 |
Step |
Apply square root on both sides |
⇒ \$\sqrt(AO^2) = \sqrt(25)\$ ⇒ AO = 5 cm |
7 |
Step |
The length of diagonal AC is 5 x 2 = 10 cm. |
|
8 |
SumUp |
Can you summarize what you’ve understood in the above steps? |
|
9 |
Choice.A |
This is correct because it match the calculated length for diagonal AC, which is 10 cm by using Pythagoras’s theorem |
10 cm |
10 |
Choice.B |
This is not correct because it does not match the calculated length for diagonal AC, which is 10 cm by using Pythagoras’s theorem |
12 cm |
11 |
Choice.C |
This is not correct because it does not match the calculated length for diagonal AC, which is 10 cm by using Pythagoras’s theorem |
14 cm |
12 |
Choice.D |
This is not correct because it does not match the calculated length for diagonal AC, which is 10 cm by using Pythagoras’s theorem |
16 cm |
13 |
Answer |
Option |
A |
14 |
SumUp |
Can you summarize what you’ve understood in the above steps? |
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