Step-3

Title: Quadrilaterals (Rhombus, Square)

Grade: 6-a Lesson: S2-L5

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

Step Type Explanation Answer

1

Problem

ABCD is a rhombus whose diagonals intersect at O. If AB = 13 cm, diagonal BD = 24 cm, find the length of diagonal AC.

2

Step

We know in rhombus, diagonals bisect each other at the right angle In ΔAOB

BO = \$(BD)/2\$ = \$24/2\$ = 12 cm

3

Formula

Using Pythagoras’s theorem in ΔAOB

\$AB^2 = AO^2 + BO^2\$

4

Step

Substitute the value in the formula

⇒ \$13^2 = AO^2 + 12^2\$

⇒ \$169 = AO^2 + 144\$

5

Step

Now simplify the equation

⇒ \$AO^2 = 169 - 144\$

⇒ \$AO^2 = 25\$

6

Step

Apply square root on both sides

⇒ \$\sqrt(AO^2) = \sqrt(25)\$

⇒ AO = 5 cm

7

Step

The length of diagonal AC is 5 x 2 = 10 cm.

8

SumUp

Can you summarize what you’ve understood in the above steps?

9

Choice.A

This is correct because it match the calculated length for diagonal AC, which is 10 cm by using Pythagoras’s theorem

10 cm

10

Choice.B

This is not correct because it does not match the calculated length for diagonal AC, which is 10 cm by using Pythagoras’s theorem

12 cm

11

Choice.C

This is not correct because it does not match the calculated length for diagonal AC, which is 10 cm by using Pythagoras’s theorem

14 cm

12

Choice.D

This is not correct because it does not match the calculated length for diagonal AC, which is 10 cm by using Pythagoras’s theorem

16 cm

13

Answer

Option

A

14

SumUp

Can you summarize what you’ve understood in the above steps?


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