Step-5

Title: Area of Rectangle

Grade: 6-a Lesson: S1-L6

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

Step Type Explanation Answer

1

Problem

The perimeter of a rectangle is 24cm , the length of the rectangle is double its width. Find the area of the rectangle.

2

Step

The perimeter of the rectangle is given,(P)

24 cm

3

Formula

Length(L) of the rectangle is double its width(W)

L = 2W

4

Step

Perimeter of the rectangle

P = 2(L + W)

5

Step

Substitute the values

24 = 2(2W + W) = 2(3W)

6

Step

After simplification sq.ft

24 = 6W

7

Step

Divide 6 on both sides

\$24/6\$ = \$(6W)/6\$

8

Step

After simplification

W = 4

9

Step

We need to determine the length of the rectangle.

L = 2W

⇒ 2(4) = 8 cm

10

Step

Area of the rectangle(A)

A = L * W

11

Step

Substitute the values

A = 4 * 8 = 32

12

Step

So, the Area of the rectangle is 32 sq.cm

13

SumUp

Can you summarize what you’ve understood in the above steps?

14

Choice.A

The rectangle’s area differs from the given option, making it the incorrect choice in this context

36 sq.cm

15

Choice.B

The rectangle’s area differs from the given option, making it the incorrect choice in this context

28 sq.cm

16

Choice.C

The rectangle’s area differs from the given option, making it the incorrect choice in this context

24 sq.cm

17

Choice.D

The correct option corresponds to the area of the rectangle, making it the accurate choice

32 sq.cm

18

Answer

Option

D

19

SumUp

Can you summarize what you’ve understood in the above steps?


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