A square has twice the perimeter of another square. If the smaller square has a side length of 4 inches, what is the side length of the larger square?

According to the information given, the larger square has twice the perimeter of the smaller square.

The perimeter(P) of a square is given by the formula

P = 4s

Perimeter of the smaller square

P = 4s

⇒ \$4 \ times 4\$

⇒ 16 inches

Now, according to the problem, the larger square has twice this perimeter:

Perimeter of the larger square = 2 * Perimeter of the smaller square

Perimeter of the larger square

P = 2 * 16 = 32 inches

Now, we know the perimeter(P) of the larger square is 32 inches. To find the side length of the larger square.

Perimeter of a square

P = 4 * s

Substitute the values

32 = 4 * s

Now, divide both sides by 4 to solve for s

⇒ \$32/4\$

⇒ \$(4s)/4\$

s = 8

So, the side length of the larger square is 8 inches.

Can you summarize what you’ve understood in the above steps?

The provided option aligns with the answer, indicating its correctness; therefore, it is the correct answer

8 inches

The provided option doesn’t align with the correct answer, making it an incorrect choice in this context

10 inches

The provided option doesn’t align with the correct answer, making it an incorrect choice in this context

12 inches

The provided option doesn’t align with the correct answer, making it an incorrect choice in this context

20 inches

Option

A

Can you summarize what you’ve understood in the above steps?