Find the surface area of a triangular pyramid whose area of the base triangle is \$28 cm^2\$, the perimeter is 16 cm, and the slant height of the pyramid is 12 cm.

The given value are

Base area of triangle = 28 sq.cm , perimeter = 16 cm and h = 12 cm

To find the surface area of a triangular pyramid formula is

\$"A_tri-pyramid" ​= 1/2 times "P" times "l" + "A_base"\$​

Now plug the value in the surface area triangular pyramid formula

\$"A_tri-pyramid" = 1/2 times 16 times 12 + 28\$

After simplification

\$"A_tri-pyramid" = 96 + 28\$

\$"A_tri-pyramid" = 124 cm^2\$

Therefore, the surface area of the triangular pyramid is \$124 cm^2\$

Can you summarize what you’ve understood in the above steps?

This is incorrect because they do not match the calculated surface area for the given values

96 sq.cm

This is not correct because it only represents the area of the base triangle, not the total surface area of the triangular pyramid

28 sq.cm

This is accurate because it shows the base triangle’s area and the overall surface area of the triangular pyramid.

124 sq.cm

This is incorrect because they do not match the calculated surface area for the given values

56 sq.cm

Option

C

Can you summarize what you’ve understood in the above steps?