The two circles are placed side by side. The first circle has a radius of 8 inches, and the second circle’s circumference is twice as long as the first circle’s circumference. Find the radius of the 2nd circle.

Radius of a first circle(r1)

8 inches

Circumference of a circle

C = 2πr

We need to determine the circumference of the first circle (C1).

C1 = \$2 \times 3.14 \ times 8\$

C1 = 50.24

The circumference of the first circle (C1) is 51.48 inches.

The circumference of the second circle is twice as long as the circumference of the first circle(C2).

\$2 \times 50.24 = 100.48\$

We need to determine the radius of the second circle (r2) by using the circumference of a circle.

⇒ C2 = \$ 2 \times π \times r2\$

⇒ \$100.48 = 2 \times 3.14 \times r2\$

⇒ r2 = \$100.48/6.28\$

After performing a division operation, the resulting value is

r2 = 16

The radius(r2) of a second circle is 16 inches.

Can you summarize what you’ve understood in the above steps?

This is not correct because it suggests a radius, which is not the correct value based on the calculations

10 inches

This is the correct answer because the radius of the second circle is indeed 16 inches

16 inches

This is not correct because it suggests a radius, which is not the correct value based on the calculations

15 inches

This is not correct because it suggests a radius, which is not the correct value based on the calculations

20 inches

Option

B

Can you summarize what you’ve understood in the above steps?