The sum of the perimeter of A and B squares is 20 cm, and the length of A court is 2cm. Then, find the size of B square.

Here the sum of A and B squares is 20 cm

A + B = 20

Given length(s) of A court is 2cm, and we know that the perimeter of a square is

A = 4s

Substitute the value s is 2, we get

A = \$4 \times 2\$

A = 8

We need to determine the length of side B squared.

8 + B = 20

Subtract 8 on both sides

8 + B - 8 = 20 -8

B = 20 - 8

Length of B square is

B = 12

The perimeter of a square B side is

B = 4s

Substitute the value B and calculate the length of each side

12 = 4s

Divide 4 on both sides

\$(12)/4 =(4s)/4\$

3 = s

s = 3

The length of the side(s) in square B is

3 cm

Can you summarize what you’ve understood in the above steps?

This match the result we found, so it’s a valid option

3 cm

This does not match the result we found, so it’s not a valid option

2 cm

This does not match the result we found, so it’s not a valid option

4 cm

This is not the correct unit, and the numerical value doesn’t match the solution obtained for the problem

12 ft

Option

A

Can you summarize what you’ve understood in the above steps?