Content Level-1 Problem-8 Click for video
| Steps | Problem | Solution |
|---|---|---|
1 |
Solve the equation |
\$ | 20+2x | = | 4x+4 | \$ |
2 |
Given equation |
\$ | 20+2x | = | 4x+4 | \$ |
3 |
Remove the both sides modules (or) absolute we get |
\$ 20+2x=4x+4 (or) 20+2x=-(4x+4) \$ |
4 |
Transver all variable terms on left hand side and all constant terms transvered on right hand side we get |
\$ 2x-4x=4-20 (or) 2x+4x=-4-20 \$ |
5 |
After simplification we get |
\$ -2x=-16 (or) 6x=-24 \$ |
6 |
Dividing on both sides by "-2","6" we get |
\$ (-2x)/-2=-16/-2 (or) (6x)/6=-24/6 \$ |
7 |
After cancellation we get |
\$ x=8 (or) x=-4 \$ |
8 |
Hence the solution of the given equation is |
\$ x= -4 (or) 8 \$ |
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