Step-1

Title: Geometric progression

Grade: 9-a Lesson: S4-L7

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

Step Type Explanation Answer

1

Problem

Find the sum of the geometric series 2 + 6 + 18 + 54 + …​ where there are 6 terms in the series.

2

Step

The given geometric series is 2,6,18,54…​

3

Step

We know that geometric progression is a series of numbers in which each term is obtained by multiplying the previous term by a fixed number, known as the common ratio.

4

Formula:

common ratio of the given geometric series is given by

\$ r = (r_2)/(r_1) = 6/2 = 3\$

5

Step

From the given data

\$a = 2 ,n =6\$

6

Formula:

Sum of the first n terms \$S_n = (a(1-r^n))/(1-r)\$

7

Step

Substitute the values in the formula

\$S_6 = (2(1-3^6))/(1-3)\$

8

Step

Simplification

\$S_6 = (2(1-729))/-2\$

9

Step

After simplification

\$S_6 = 728\$

10

Step

Sum of the 6 terms of geometric series is 728

11

Answer

B


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