Lesson Example Discussion Quiz: Class Homework |
Step-5 |
Title: Consecutive terms of A.P |
Grade: 9-a Lesson: S4-L5 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
| Step | Type | Explanation | Answer |
|---|---|---|---|
1 |
Problem |
The fourth term of an A.P. is 18. The sum of the fifth and seventh terms of the A.P. is 44. Find its common difference |
|
2 |
Step |
Let the first term of A.P. |
\$ a \$ |
3 |
Step |
Common difference |
\$ d \$ |
4 |
Step |
The fourth term of an A.P. is |
\$ a_4 = 18\$ |
5 |
Formula: |
The nth term of an A.P. is |
\$a_n = a+(n-1)d\$ |
6 |
Step |
The fourth term of an A.P. is |
\$ a_4 = a + (4-1)d\$ |
7 |
Step |
Substitute \$a_4\$ value |
\$ 18 = a + 3d\$ |
8 |
Step |
After simplification |
\$ a = 18 - 3d -> (1)\$ |
9 |
Step |
The sum of the fifth and seventh terms of the A.P. is |
\$ a_5 + a_7 = 44\$ |
10 |
Step |
After simplification |
\$ a + 4d + a + 6d = 44\$ |
11 |
Step |
After simplification |
\$ 2a + 10d = 44\$ |
12 |
Step |
After simplification |
\$ \cancel2(a + 5d) = \cancel44^22\$ |
13 |
Step |
After simplification |
\$ a + 5d = 22\$ |
14 |
Step |
After simplification |
\$ a = 22 - 5d -> (2)\$ |
15 |
Step |
From (1) and (2) |
\$18 - 3d = 22 - 5d \$ |
16 |
Step |
After simplification |
\$5d - 3d = 22 - 18 \$ |
17 |
Step |
After simplification |
\$ \cancel2^1d = \cancel4^2 \$ |
18 |
Step |
After simplification |
\$ d = 2 \$ |
19 |
Answer |
C |
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Tutor: Questions
| Seq | Type | Question | Audio |
|---|---|---|---|
1 |
Problem |
What did you learn from this problem? |
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2 |
Clue |
What did you learn from the clues? |
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3 |
Hint |
What did you learn from the Hints? |
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4 |
Step |
What did you learn from the Steps? |
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5 |
Step |
How can we improve the Steps? |
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