Step-4

Title: Consecutive terms of A.P

Grade: 9-a Lesson: S4-L5

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

Step Type Explanation Answer

1

Problem

Find the middle term of the AP 7,13,19,…, 343.

2

Step

Given AP: 7,13,19,…, 343

3

Clue

Given

\$ a = 7\$

4

Formula:

Common difference

\$ d = a_2 - a_1 = 13 - 7 = 6\$

5

Clue

The \$n^(th)\$ term

\$ a_n = 343\$

6

Hint

Now

\$a_n = a + (n-1)d\$

7

Step

Substitute a,d and \$a_n\$

\$ 343 = 7 + (n-1)6\$

8

Step

After simplification

\$ 343 = 7 + 6n - 6\$

9

Step

After simplification

\$ 343 = 6n + 1\$

10

Step

After simplification

\$ 6n = 343 - 1 = 342\$

11

Step

After simplification

\$ n = \cancel342^(57)/\cancel6 \$

12

Step

After simplification

\$ n = 57 \$

13

Step

The middle term of A.P. is

\$S_n = (n+1)/2 \$

14

Step

Substitute n value

\$S_57 = (57+1)/2 = \$

15

Step

After simplification

\$S_57 = \cancel58^(29)/\cancel2 = 29 \$th term of A.P.

16

Step

The 29 th term of A.P. is

\$a_29 = 7 + (29 - 1)6 \$

17

Step

After simplification

\$a_29 = 7 + 28 \times 6 \$

18

Step

After simplification

\$a_29 = 7 + 168 = 175 \$

19

Step

Thus the middle term of the A.P. is

\$175 \$

20

Answer

B

Tutor: Questions

Seq Type Question Audio

1

Problem

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2

Clue

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3

Hint

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4

Step

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5

Step

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