Step-3

Title: Consecutive terms of A.P

Grade: 9-a Lesson: S4-L5

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

Step Type Explanation Answer

1

Problem

If the sum of first 8 terms of an A.P. is 64 and that of its first 18 terms is 324, find the sum of first n terms of the A.P.

2

Step

Sum of first 8 terms

\$S_8 = 64\$

3

Step

Sum of first 18 terms

\$S_18 = 324\$

4

Formula:

We know that sum of n terms of A.P. is

\$ S_n = n/2(2a + (n-1)d)\$

5

Step

Sum of 8 terms of A.P.

\$ S_8 = 8/2(2a + (8-1)d)\$

6

Step

Substitute the value of \$S_8\$

\$ 64 = 4(2a + 7d) \$

7

Step

After simplification

\$ \cancel64^16/\cancel4 = 2a + 7d \$

8

Step

After cancellation

\$ 2a + 7d = 16 -> (1)\$

9

Step

Sum of 18 terms of A.P.

\$ S_18 = 18/2(2a + (18-1)d)\$

10

Step

Substitute the value of \$S_18\$

\$ 324 = 9(2a + 17d) \$

11

Step

After simplification

\$ \cancel324^36/\cancel9^1 = 2a + 17d \$

12

Step

After cancellation

\$ 2a + 17d = 36 -> (2)\$

13

Step

Subtracting equation (1) from equation (2)

\$2a + 17d - (2a + 7d) = 36 - 16\$

14

Step

After subtraction

\$ 2a + 17d - 2a - 7d = 20\$

15

Step

After simplification

\$ \cancel10^1d = \cancel20^2\$

16

Step

After cancellation

\$ d = 2\$

17

Step

Substitute d value in \$eq^n (1)\$

\$ 2a + 7(2) = 16 \$

18

Step

After simplification

\$ 2a + 14 = 16 \$

19

Step

After simplification

\$ 2a = 16 - 14 = 2 \$

20

Step

After simplification

\$ a = \cancel2^1/\cancel2^1 \$

21

Step

After simplification

\$ a = 1\$

22

Step

Sum of n terms of A.P. is

\$S_n = n/2(2a + (n-1)d) \$

23

Step

Substitute a,d values

\$S_n = n/2(2(1) + (n-1)2) \$

24

Step

After simplification

\$S_n = n/2(\cancel2 + 2n - \cancel2) \$

25

Step

After simplification

\$S_n = n/\cancel2( \cancel2n ) \$

26

Step

After simplification

\$S_n = n^2 \$

27

Answer

D

Tutor: Questions

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1

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2

Clue

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3

Hint

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4

Step

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5

Step

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