Lesson Example Discussion Quiz: Class Homework |
Step-5 |
Title: Find the equation of a line passes through the point and has a Y-intercept of Number |
Grade: 9-a Lesson: S2-L8 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
| Step | Type | Explanation | Answer |
|---|---|---|---|
1 |
Problem |
A line passes through the point and has a Y-intercept of 8: |
|
2 |
Hint |
Consider |
\$ x = -3 , y = 9 \$ & \$ b = 8 \$ |
3 |
Formula: |
Using Slope-intercept form |
\$ y = mx + b \$ |
4 |
Step |
Substituting '\$ x , y , b\$' values |
\$9 = m(-3) + 8 \$ |
5 |
Step |
After substituting the values |
\$ 9 = -3m + 8 \$ |
6 |
Step |
Find the m value |
\$ 3m = 8 - 9 \$ |
7 |
Step |
Now finding the the m value |
\$ 3m = -1 \$ |
8 |
Step |
After finding the m value |
\$ m = -1/3 \$ |
9 |
Step |
Now Substitute m , b values in the Slope-intercept form we get |
\$ y = (-1/3)x + 8 \$ |
10 |
Step |
Taking LCm as 3 |
\$ y = (-x + (8\times3))/3 \$ |
11 |
Step |
Simplifying the equation |
\$ y = (-x + 24)/3 \$ |
12 |
Step |
After simplification |
\$ 3y = -x + 24 \$ |
13 |
Step |
Converting to the equation form |
\$ x + 3y = 24 \$ |
14 |
Step |
After Converting to the equation form |
\$ x + 3y - 24 = 0 \$ |
15 |
Answer |
B |
|
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