Lesson Example Discussion Quiz: Class Homework |
Step-2 |
Title: Find the equation of a line passes through the point and has a Y-intercept of Number |
Grade: 9-a Lesson: S2-L8 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
| Step | Type | Explanation | Answer |
|---|---|---|---|
1 |
Problem |
A line passes through the point and has a Y-intercept of 4: |
|
2 |
Formula: |
Consider |
\$ x = -4 , y = 9 \$ & \$ b = 4 \$ |
3 |
Hint |
Using Slope-intercept form |
\$*y = mx + b*\$ |
4 |
Step |
Substituting x , y , b values |
\$9 = m(-4) + 4 \$ |
5 |
Step |
After Substituting x , y , b values |
\$ 9 = -4m + 4 \$ |
6 |
Step |
Now find the value of m |
\$ 4m = 4 - 9 \$ |
7 |
Step |
Find the value of m |
\$ 4m = -5 \$ |
8 |
Step |
After finding the value of m |
\$ m = -5/4 \$ |
9 |
Step |
Now Substitute m , b values in the Slope-intercept form we get |
\$ y = (-5/4)x + 4 \$ |
10 |
Step |
Taking LCm as 4 |
\$ y = (-5x + (4\times4))/4 \$ |
11 |
Step |
Simplifying the equation |
\$ y = (-5x + 16)/4 \$ |
12 |
Step |
After simplification |
\$ 4y = -5x + 16 \$ |
13 |
Step |
Converting to the equation form |
\$ 5x + 4y = 16 \$ |
14 |
Step |
After converting to the equation form |
\$ 5x + 4y - 16 = 0 \$ |
15 |
Answer |
B |
|
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