Step-5

Title: Find the roots of the quadratic equation

Grade: 9-a Lesson: S1-L7

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

Step Type Explanation Answer

1

Problem

Find the roots of the quadratic equation:
\$ (-x)(5x + (-5)) = 10 \$

2

Step

Now converted to

\$ax^2+bx+c=0\$

3

Step

after converting

\$ -5x^2 + 5x - 10 = 0 \$

4

Step

By taking "-5" has common multiple we get

\$ -5(x^2 - x + 2) = 0 \$

5

Step

After eleminating "-5" we get

\$ x^2 - x + 2 = 0 \$

6

Step

Since the equation is in the form of

\$ax^2+bx+c=0\$

7

Formula:

formula

\$ x = (-b \pm \sqrt (b^2 - 4ac))/(2a) \$

8

Step

Substitute the values

\$ a = 1, b = -1 , c = 2\$

9

Step

converting the equation into formula by substituting the values

\$ x = (-(-1) \pm \sqrt ((-1)^2 - 4(1)(2)))/(2(1)) \$

10

Step

Simplifing the equation

\$ x = (1 \pm \sqrt (1 - 8))/2 \$

11

Step

Simplifing the equation

\$ x = (1 \pm \sqrt (-7))/2 \$

12

Step

We know that [i^2 = -1]

\$ x = (1 \pm \sqrt (i^2 7))/2 \$

13

Step

After simplification we get

\$ x = (1 \pm i\sqrt (7))/2\$

14

Answer

B

Tutor: Questions

Seq Type Question Audio

1

Problem

What did you learn from this problem?

2

Clue

What did you learn from the clues?

3

Hint

What did you learn from the Hints?

4

Step

What did you learn from the Steps?

5

Step

How can we improve the Steps?


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