Step-3

Title: Find the roots of the quadratic equation

Grade: 9-a Lesson: S1-L7

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

Step Type Explanation Answer

1

Problem

Find the roots of the quadratic equation:
\$ (x)(6x - 17) = -12 \$

2

Problem

Now converted to

\$ax^2+bx+c=0\$

3

Step

after converting

\$ 6x^2 - 17x + 12 = 0 \$

4

Step

Since the equation is in the form of

\$ax^2+bx+c=0\$

5

Formula:

formula

\$ x = (-b \pm \sqrt (b^2 - 4ac))/(2a) \$

6

Step

Substitute the values

\$ a = 6, b = -17 , c = 12\$

7

Step

converting the equation into formula by substituting the values

\$ x = (-(-17) \pm \sqrt ((-17)^2 - 4(6)(12)))/(2(6)) \$

8

Step

Simplifing the equation

\$ x = (17 \pm \sqrt (289-288))/12 \$

9

Step

We know that [i^2 = -1]

\$ x = (17 \pm \sqrt (1^2))/4 \$

10

Step

After simplification we get

\$ x = (17 \pm 1)/12\$

11

Step

After simplification we get

\$ x = (17 + 1)/12 , (17- 1)/12 \$

12

Step

After simplification we get

\$ x = (\cancel18^3)/\cancel12^2 , (\cancel16^4)/\cancel12^3 \$

13

Step

After cancellation we get

\$ x = 3/2 , 4/3\$

14

Answer

C

Tutor: Questions

Seq Type Question Audio

1

Problem

What did you learn from this problem?

2

Clue

What did you learn from the clues?

3

Hint

What did you learn from the Hints?

4

Step

What did you learn from the Steps?

5

Step

How can we improve the Steps?


Copyright © 2020-2022 saibook.us Contact: info@saibook.us Version: 1.5 Built: 20-February-2023 08:10 PM EST