Lesson Example Discussion Quiz: Class Homework |
Step-2 |
Title: Find the roots of the quadratic equation |
Grade: 9-a Lesson: S1-L7 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
Step | Type | Explanation | Answer |
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1 |
Problem |
Find the roots of the quadratic equation: |
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2 |
Step |
Now converted to |
\$ax^2+bx+c=0\$ |
3 |
Step |
after converting |
\$ -4x^2 - 6x - 6 = 0 \$ |
4 |
Step |
By taking "-2" has common multiple we get |
\$ -2(2x^2 + 3x + 3) = 0 \$ |
5 |
Step |
After eleminating "-2" we get |
\$ 2x^2 + 3x + 3 = 0 \$ |
6 |
Step |
Since the equation is in the form of |
\$ax^2+bx+c=0\$ |
7 |
Formula: |
formula |
\$ x = (-b \pm \sqrt (b^2 - 4ac))/(2a) \$ |
8 |
Step |
Substitute the values |
\$ a = 2, b = 3 , c = 3\$ |
9 |
Step |
converting the equation into formula ny substituting the values |
\$ x = (-3 \pm \sqrt (3^2 - 4(2)(3)))/(2(2)) \$ |
10 |
Step |
Simplifing the equation |
\$ x = (-3 \pm \sqrt (-15))/4 \$ |
11 |
Step |
We know that [i^2 = -1] |
\$ x = (-3 \pm \sqrt (i^2 15))/4 \$ |
12 |
Step |
After simplification we get |
\$ x = (-3 \pm i\sqrt (15))/4\$ |
13 |
Answer |
B |
Tutor: Questions
Seq | Type | Question | Audio |
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1 |
Problem |
What did you learn from this problem? |
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2 |
Clue |
What did you learn from the clues? |
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3 |
Hint |
What did you learn from the Hints? |
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4 |
Step |
What did you learn from the Steps? |
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5 |
Step |
How can we improve the Steps? |
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