Find the roots of the quadratic equation:
\$ 2x^2 - 8x + 4 = 0 \$

the equation is in the form of

\$ax^2+bx+c=0\$

by using this formula

\$ x = (-b \pm \sqrt (b^2 - 4ac))/(2a) \$

converting the equation into formula

\$ x = (-(-8) ± \sqrt((-8)^2 - 4\times(2)\times(4)))/(2\times(2)) \$

Simplifing the equation

\$ x = (8 ± \sqrt(64 - 32))/4 \$

Subtract the numbers under square root

\$ x = (8 ± \sqrt(32))/4 \$

Take the multiples of '32'

\$ x = (8 ± \sqrt(16\times2))/4\$

After simplification we get

\$ x =(8 ± 4\sqrt(2))/4\$

Taking common factor as [4] in the Numerator

\$ x = (4(2 ± \sqrt(2)))/4 \$

calculating the terms

\$ x = (\cancel(4)^1(2 ± \sqrt(2)))/\cancel(4)^1 \$

After Cancellation we get

\$ x = 2 ± \sqrt(2) \$

Answer

C