Step-1

Title: Roots of the quadratic equation

Grade: 9-a Lesson: S1-L6

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

Step Type Explanation Answer

1

Problem

Find the roots of the quadratic equation:
\$ 2x^2 - 4x - 8 = 0 \$

2

Step

given equation is

\$ax^2+bx+c=0\$ then

3

Formula:

formula for find the roots of the equation

\$ x = (-b \pm \sqrt (b^2 - 4ac))/(2a) \$

4

Step

after coverting the equation into formula

\$ x = (-(-4) ± \sqrt((-4)^2 - 4\times(2)\times(-8)))/(2\times(2)) \$

5

Step

Simplifing the equation

\$ x = (4 ± \sqrt(16 +64))/4 \$

6

Hint

Add the numbers under the square root

\$ x = (4 ± \sqrt(80))/4 \$

7

Hint

Take the multiples of '80' to simplify

\$ x = (4 ± \sqrt(16\times5))/4\$

8

Step

After simplification we get

\$ x = (4 ± 4\sqrt(5))/4\$

9

Hint

Taking common factor as [4]in the Numerator

\$ x = (4(1 ± \sqrt(5)))/4 \$

10

Step

calculating the terms

\$ x = (\cancel(4)(1 ± \sqrt(5)))/\cancel(4) \$

11

Step

After Cancellation we get

\$ x = 1 ± \sqrt(5) \$ 12

Tutor: Questions

Seq Type Question Audio

1

Problem

What did you learn from this problem?

2

Clue

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3

Hint

What did you learn from the Hints?

4

Step

What did you learn from the Steps?

5

Step

How can we improve the Steps?


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