Lesson Example Discussion Quiz: Class Homework |
Step-4 |
Title: Calculate the equation |
Grade: 8-a Lesson: S3-L8 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
| Step | Type | Explanation | Answer |
|---|---|---|---|
1 |
Problem |
Calculate the equation |
|
2 |
Step |
Adding - 2 on both sides we get |
\$ 3| x + 4 | + \cancel2 - \cancel2 = 16 - 2 \$ |
3 |
Step |
After cancellation we get |
\$ 3| x + 4 | = 14 \$ |
4 |
Step |
Dividing on both sides by 3 we get |
\$ \cancel3/\cancel3| x + 4 | = 14/3 \$ |
5 |
Step |
After cancellation we get |
\$ | x + 4 | = 14/3 \$ |
6 |
Formula: |
By using formula |
\$| x | = a\$ |
7 |
Hint |
By removing mod we get(+) or (-) |
\$x = a (or) x = - a \$ |
8 |
Step |
Here 'a' is \$14/3\$ |
\$ x + 4 = 14/3 (or) x + 4 = - 14/3 \$ |
9 |
Step |
Adding - 4 on both sides we get |
\$ x + \cancel4 - \cancel4 = 14/3 - 4 (or) x + \cancel4 - \cancel4 = - 14/3 - 4 \$ |
10 |
Step |
After cancellation we get |
\$ x = 14/3 - 4 (or) x = - 14/3 - 4 \$ |
11 |
Hint |
Taking LCM as 3 |
|
12 |
Step |
After simplification |
\$ x = (14 - 12)/3 (or) x = (-14 - 12)/3 \$ |
13 |
Step |
After simplification we get |
\$ x = 2/3 (or) x = - 26/3 \$ |
14 |
Answer |
A |
|
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