Lesson Example Discussion Quiz: Class Homework |
Step-3 |
Title: Calculate the equation |
Grade: 8-a Lesson: S3-L8 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
Step | Type | Explanation | Answer |
---|---|---|---|
1 |
Problem |
Calculate the equation |
|
2 |
Step |
Adding - 8 on both sides we get |
\$ 6| x + 1 | + \cancel8 - \cancel8 = 12 - 8 \$ |
3 |
Step |
After cancellation we get |
\$ 6| x + 1 | = 4 \$ |
4 |
Step |
Dividing on both sides by 6 we get |
\$ \cancel6/\cancel6| x + 1 | = \cancel4^2/\cancel6^3 \$ |
5 |
Step |
After cancellation we get |
\$ | x + 1 | = 2/3 \$ |
6 |
Formula: |
By using formula |
\$| x | = a\$ |
7 |
Hint |
By removing mod we get(+) or (-) |
\$x = a (or) x = - a \$ |
8 |
Step |
Here 'a' is \$2/3\$ |
\$ x + 1 = 2/3 (or) x + 1 = - 2/3 \$ |
9 |
Step |
Adding - 1 on both sides we get |
\$ x + \cancel1 - \cancel1 = 2/3 - 1 (or) x + \cancel1 - \cancel1 = - 2/3 - 1 \$ |
10 |
Step |
After cancellation we get |
\$ x = 2/3 - 1 (or) x = - 2/3 - 1 \$ |
11 |
Hint |
Taking LCM as 3 |
|
12 |
Step |
After simplification |
\$ x = (2 - 3)/3 (or) x = (-2 - 3)/3 \$ |
13 |
Step |
After simplification we get |
\$ x = -1/3 (or) x = - 5/3 \$ |
14 |
Answer |
B |
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