Lesson Example Discussion Quiz: Class Homework |
Step-5 |
Title: Square roots and cube roots |
Grade: 8-a Lesson: S1-L5 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
| Step | Type | Explanation | Answer |
|---|---|---|---|
1 |
Problem |
simplify the following: |
|
2 |
Step |
To simplify the given expressions: |
|
3 |
Step |
First, notice that both terms have the same radical \$\sqrt 26\$. We can combine them: |
\$7\sqrt26 + 11\sqrt26\$ \$(7 + 11)\sqrt 26\$ \$18\sqrt 26\$ |
4 |
Step |
To simplify the given expressions: |
B.\$\sqrt18\$ |
5 |
Step |
To simplify \$\sqrt18\$, we need to factorize the number under the square root: |
\$18 = 9 \times 2 = 3^2 \times 2\$ |
6 |
Step |
So, we can rewrite \$\sqrt18\$ as: |
\$\sqrt18\$ = \$\sqrt(3^2 \times 2)\$ = \$3\sqrt2\$ |
7 |
Step |
Therefore, the correct answers are \$18\sqrt26\$ and \$3\sqrt2\$. |
|
8 |
Choice.A |
The first part doesn’t match the coefficient in the simplified expression, and the second part doesn’t match the radical term.So, Option A doesn’t match |
\$18\sqrt35\$ and \$\sqrt3\$ |
9 |
Choice.B |
Both parts match exactly with the simplified expression. Therefore, Option B is the correct one |
\$18\sqrt26\$ and \$3\sqrt2\$ |
10 |
Choice.C |
Option C doesn’t align because the numerical coefficient in the first part and the radical term in the second part don’t correspond to those in the simplified expression |
\$26\sqrt62\$ and \$5\sqrt3\$ |
11 |
Choice.D |
Neither the first nor the second part matches the simplified expression. So, Option D doesn’t match |
\$18\sqrt18\$ and \$3\sqrt3\$ |
12 |
Answer |
Option |
B |
13 |
Sumup |
Can you summarize what you’ve understood in the above steps? |
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