Lesson Example Discussion Quiz: Class Homework |
Step-4 |
Title: Square roots and cube roots |
Grade: 8-a Lesson: S1-L5 |
Explanation: Hello Students, time to practice and review the steps for the problem. |
Lesson Steps
Step | Type | Explanation | Answer |
---|---|---|---|
1 |
Problem |
Solve for x if \$\sqrt("x" + 3) - \sqrt("x") = 3\$. |
|
2 |
Step |
The given equation is |
\$\sqrt("x" + 3) - \sqrt("x") = 3\$ |
3 |
Step |
To solve this equation, let’s first isolate one of the square roots. We’ll isolate \$\sqrt("x")\$ by adding \$\sqrt("x")\$ to both sides: |
\$\sqrt("x" + 3) - \sqrt("x") + \sqrt("x") = 3 + \sqrt("x")\$ |
4 |
Step |
Now, let’s square both sides to eliminate the square roots: |
\$(\sqrt("x" + 3))^2 = (3 + \sqrt("x"))^2\$ \$(("a" + "b")^2 = "a"^2 + 2"ab" + "b"^2)\$ |
5 |
Step |
Simplify the equation |
x + 3 = 9 + \$ 2 times 3 times \sqrt("x")\$ + x x + 3 = 9 + \$6 \sqrt("x")\$ + x |
6 |
Step |
Then move constant terms to one side and x terms to another side |
x - x - \$6\sqrt("x")\$ = 9 - 3 \$- 6\ sqrt("x") = 6\$ \$\sqrt("x") = - 6/6\$ \$\sqrt("x") = - 1\$ |
7 |
Step |
Square both sides to solve for x: |
\$(\sqrt("x"))^2 = (- 1)^2\$ x = 1 |
8 |
Step |
So, the solution is x = 1. |
|
9 |
Choice.A |
Option A is incorrect because the solution for x does not equal 3 |
3 |
10 |
Choice.B |
Incorrect since the value of x does not equate to 2 in the solution |
2 |
11 |
Choice.C |
Option C is inaccurate as the solution for x is not 4, as stated |
4 |
12 |
Choice.D |
Hence, the accurate solution is option D, where x equals 1 |
1 |
13 |
Answer |
Option |
D |
14 |
Sumup |
Can you summarize what you’ve understood in the above steps? |
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