If the polynomials f(x) is evenly divisible by x - 5 and the polynomials g(x) = f(x) + 4, what is the value of g(5)?

The given polynomials are

f(x) is evenly divisable by x - 5 and g(x) = f(x) + 4

If f(x) is evenly divisible by x − 5, then f(5) = 0, because if x − 5 is a factor of f(x), then when you substitute x = 5, you get 0.

Since f(x) is evenly divisible by x − 5, so

f(5) = 0

f(5) = 0 is plug the g(x) then simplify

g(x ) = f(x) + 4
g(5) = f(5) + 4
g(5) = 0 + 4
g(5) = 4

Therefore, the value of g(5) is 4.

The calculation shows g(5) as 4, not -5, which is incorrect based on the calculation

-5

Incorrect: The value of g(5) is positive, not negative, according to the calculation

-4

Incorrectly computed: g(5) evaluates to 4, deviating from the anticipated result of 5

5

Correct: The calculation yields g(5) as 5, by the expected result

4

Option

D

Can you summarize what you’ve understood in the above steps?