1

Find the negative value of \$ x/y\$

\$ (4(2x)^2 + (3y)^2)/(xy) = -24 \$

2

Moving "\$ xy \$" to left side we get

\$ (4(2x)^2 + (3y)^2) = -24(xy) \$

3

After simplification we get

\$ 4(2x)^2 + 24xy + (3y)^2 = 0 \$

4

Using identity \$a^2 + 2ab + b^2 = (a + b)^2\$, we get

\$ (2(2x) + 3y)^2 = 0 \$

5

Applying squareroot on both sides we get

\$ \sqrt(2(2x) + 3y)^2 = \sqrt0 \$

6

Cancelling Square & Squareroot we get

\$ (2(2x) + 3y) = 0 \$

7

Moving "\$ 3y \$" to left side we get

\$ 2(2x) = -3y \$

8

Transforming the above equation into \$ x/y \$ form, we get

\$ 4x = -3y \$
\$ 4x/y=-3 \$
\$ x/y=-3/4 \$

9

The negative valve of "\$ x/y \$" is

\$ x/y=-3/4\$

10

Answer

B = \$ x/y = -3/4 \$