1

Find the postive value of \$ x/y\$

\$ (49x^2 + 64y^2)/(xy) = 112 \$

2

Moving "\$ xy \$" to left side we get

\$ (49x^2 + 64y^2) = 112(xy) \$

3

After simplification we get

\$ 49x^2 -112(xy) + 64y^2 = 0 \$

4

Using identity \$a^2 - 2ab + b^2 = (a - b)^2\$, we get

\$ (7x - 8y)^2 = 0 \$

5

Applying squareroot on both sides we get

\$ \sqrt(7x - 8y)^2 = \sqrt0 \$

6

Cancelling Square & Squareroot we get

\$ (7x - 8y) = 0 \$

7

Moving "\$ -8y \$" to left side we get

\$ (7x = 8y) \$

8

Transforming the above equation into \$ x/y \$ form, we get

\$ 7x = 8y \$
\$ 7x/y=8 \$
\$ x/y=8/7 \$

9

The positive valve of "\$ x/y \$" is

\$ x/y=8/7 \$

10

Answer

C = \$ x/y = 8/7 \$