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Step-5

Title: Solve

Grade: 7-b Lesson: S5-L9

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

Steps	Problem	Solution
1	Solve	\$ \sqrt{\frac{x + 3}{3x - 2}} = 7 \$
2	Apply square on both sides	\$ (\sqrt{\frac{x + 3}{3x - 2}})^2 = (7)^2 \$
3	After canceling square and squareroot	\$ \frac{x + 3}{3x - 2} = 49 \$
4	Move \$ {3x - 2} \$ to right side	\$ x + 3 = 49(3x - 2) = 147x - 98 \$
5	Move variables to left side	\$ x - 147x = -98 - 3 \$
6	After simplification	\$ -146x = -101 \$
7	Dividing on both sides by '\$-146\$' of the equality	\$ \cancel(-146)/\cancel(-146)x = \cancel(-)/\cancel(-) (101/146) \$
8	After cancelation	\$ x = 101/146 \$
9	Answer	A = \$ x = 101/146 \$

Steps

Problem

Solution

Solve

\$ \sqrt{\frac{x + 3}{3x - 2}} = 7 \$

Apply square on both sides

\$ (\sqrt{\frac{x + 3}{3x - 2}})^2 = (7)^2 \$

After canceling square and squareroot

\$ \frac{x + 3}{3x - 2} = 49 \$

Move \$ {3x - 2} \$ to right side

\$ x + 3 = 49(3x - 2) = 147x - 98 \$

Move variables to left side

\$ x - 147x = -98 - 3 \$

After simplification

\$ -146x = -101 \$

Dividing on both sides by '\$-146\$' of the equality

\$ \cancel(-146)/\cancel(-146)x = \cancel(-)/\cancel(-) (101/146) \$

After cancelation

\$ x = 101/146 \$

Answer

A = \$ x = 101/146 \$