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Step-4

Title: Solve

Grade: 7-b Lesson: S5-L9

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

Steps	Problem	Solution
1	Solve	\$ \sqrt{\frac{10x - 5}{x - 2}} = 5 \$
2	Apply square on both sides	\$ (\sqrt{\frac{10x - 5}{x - 2}})^2 = (5)^2 \$
3	After canceling square and squareroot	\$ \frac{10x - 5}{x - 2} = 25 \$
4	Move \$ {x - 2} \$ to right side	\$ 10x - 5 = 25(x - 2) = 25x - 50 \$
5	Move variables to right side	\$ 10x - 25x = -50 + 5 \$
6	After simplification	\$ -15x = -45 \$
7	Dividing on both sides by '\$-15\$' of the equality	\$ \cancel(-15)/\cancel(-15)x = \cancel(-45)^3/\cancel(-15)^1 \$
8	After cancelation	\$ x = 3 \$
9	Answer	B = \$ x = 3 \$

Steps

Problem

Solution

Solve

\$ \sqrt{\frac{10x - 5}{x - 2}} = 5 \$

Apply square on both sides

\$ (\sqrt{\frac{10x - 5}{x - 2}})^2 = (5)^2 \$

After canceling square and squareroot

\$ \frac{10x - 5}{x - 2} = 25 \$

Move \$ {x - 2} \$ to right side

\$ 10x - 5 = 25(x - 2) = 25x - 50 \$

Move variables to right side

\$ 10x - 25x = -50 + 5 \$

After simplification

\$ -15x = -45 \$

Dividing on both sides by '\$-15\$' of the equality

\$ \cancel(-15)/\cancel(-15)x = \cancel(-45)^3/\cancel(-15)^1 \$

After cancelation

\$ x = 3 \$

Answer

B = \$ x = 3 \$