1

Solve

\$ \sqrt{\frac{3x - 1}{x - 1}} = 2 \$

2

Apply square on both sides

\$ (\sqrt{\frac{3x - 1}{x - 1}})^2 = (2)^2 \$

3

After canceling square and squareroot

\$ \frac{3x - 1}{x - 1} = 4 \$

4

Move \$ {x - 1} \$ to right side

\$ 3x - 1 = 4(x - 1) = 4x - 4 \$

5

Move variables to left side

\$ 3x - 4x = -4 + 1 \$

6

After simplification

\$ -x = -3 \$

7

canceling "-" on both sides

\$ \cancel(-) x = \cancel(-) 3 \$

8

After cancelation

\$ x = 3 \$

9

Answer

D = \$ x = 3 \$