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Step-1

Title: Solve

Grade: 7-b Lesson: S5-L9

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

Steps	Problem	Solution
1	Solve	\$ \sqrt{\frac{2x + 1}{x - 1}} = 1 \$
2	Apply square on both sides	\$ (\sqrt{\frac{2x + 1}{x - 1}})^2 = (1)^2 \$
3	After canceling square and squareroot	\$ \frac{2x + 1}{x - 1} = 1 \$
4	Move \$ {x - 1} \$ to right side	\$ 2x + 1 = x - 1 \$
5	move variables to left side	\$ 2x - x = -1 - 1 \$
6	After simplification	\$ x = -2 \$
7	Answer	B = \$ x = -2 \$

Steps

Problem

Solution

Solve

\$ \sqrt{\frac{2x + 1}{x - 1}} = 1 \$

Apply square on both sides

\$ (\sqrt{\frac{2x + 1}{x - 1}})^2 = (1)^2 \$

After canceling square and squareroot

\$ \frac{2x + 1}{x - 1} = 1 \$

Move \$ {x - 1} \$ to right side

\$ 2x + 1 = x - 1 \$

move variables to left side

\$ 2x - x = -1 - 1 \$

After simplification

\$ x = -2 \$

Answer

B = \$ x = -2 \$