1

Solve

\$ 15/x^2 + 1/x^2 - 5/x = 7/x \$

2

Taking like terms together

\$ 15/x^2 + 1/x^2 = 7/x + 5/x \$

3

After simplification

\$ 16/x^2 = 12/x \$

4

Multiplying on both sides with \$ x^2 \$

\$ 16/\cancel(x^2) \cancel(x^2) = 12/\cancel(x) \cancel(x^2)^x \$

5

After simplification

\$ 16 = 12x \$

6

Dividing on both sides by '\$ 12 \$' of the equality

\$ \cancel(16)^4/\cancel(12)^3 = \cancel(12)/\cancel(12)x \$

7

After cancelation

\$ 4/3 = x \$

8

Answer

B = \$ x = 4/3\$