SaiBook.us Algebra

Home Course Section Lessons: L1 L2 L3 L4 L5 L6 L7 L8 L9 L10

Register Enroll

Step-4

Title: Find the variable value

Grade: 7-b Lesson: S3-L9

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

Steps	Problem	Solution
1	Find the value of '\$x\$'	\$ 9^(x + 10) = 3^((2(2/3))) \$
2	If Bases are equal powers also equal	\$ 3^(2(x+10)) = 3^((2(2/3)))\$ \$ 2(x+10) = (4/3)\$
3	After Simplification, we get	\$2x+20 = 4/3\$
4	Move constants to the right side	\$ 2x = 4/3 - 20 \$
5	Taking LCM as \$3\$	\$ 2x = (4-60)/3 \$ \$ x = \cancel(-56)^28/\cancel(6)^3 \$
5	After simplification	\$ x = -28/3 \$
6	Answer	B = \$ x = -28/3 \$

Steps

Problem

Solution

Find the value of '\$x\$'

\$ 9^(x + 10) = 3^((2(2/3))) \$

If Bases are equal powers also equal

\$ 3^(2(x+10)) = 3^((2(2/3)))\$

\$ 2(x+10) = (4/3)\$

After Simplification, we get

\$2x+20 = 4/3\$

Move constants to the right side

\$ 2x = 4/3 - 20 \$

Taking LCM as \$3\$

\$ 2x = (4-60)/3 \$

\$ x = \cancel(-56)^28/\cancel(6)^3 \$

After simplification

\$ x = -28/3 \$

Answer

B = \$ x = -28/3 \$