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Step-2

Title: Solve the equation

Grade: 7-b Lesson: S2-L7

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

Steps	Problem	Solution
1	Solve	\$ 1(30 - x/2)= -(x/3 - 15) \$
2	After simplification	\$ 30 - x/2 = -x/3 + 15 \$
4	Move Variable terms to the left side and constant terms to the right side	\$ x/3 - x/2 = 15 - 30 \$
5	Taking LCM as '\$6\$'	\$ (2x - 3x)/6 = - 15 \$
6	After Subtraction	\$ - x/6 = - 15 \$
7	Multiplying with '\$-6\$' on both sides	\$ -x/\cancel6 \times (-\cancel6)= (-15) \times (-6) \$
8	After cancelation	\$ x = 90 \$
9	Answer	D = \$ x = 90 \$

Steps

Problem

Solution

Solve

\$ 1(30 - x/2)= -(x/3 - 15) \$

After simplification

\$ 30 - x/2 = -x/3 + 15 \$

Move Variable terms to the left side and constant terms to the right side

\$ x/3 - x/2 = 15 - 30 \$

Taking LCM as '\$6\$'

\$ (2x - 3x)/6 = - 15 \$

After Subtraction

\$ - x/6 = - 15 \$

Multiplying with '\$-6\$' on both sides

\$ -x/\cancel6 \times (-\cancel6)= (-15) \times (-6) \$

After cancelation

\$ x = 90 \$

Answer

D = \$ x = 90 \$