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Step-3

Title: Solve the equation

Grade: 7-b Lesson: S2-L6

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

Steps	Problem	Solution
1	Solve	\$ 1/10 z - 9 = 3/5 z - 19\$
2	Move Variable terms to the left side and constant terms to the right side	\$ (z/10) + ((3z)/5) = -19 + 9 \$
3	Taking LCM as '\$10\$'	\$ (z + 6z)/10 = -10/1\$
4	By using cross multiplication	\$ z + 6z = -100\$
5	After Addition	\$ 7z = -100 \$
6	Dividing on both sides by '\$7\$' of the equality	\$ \cancel(7)^1/ \cancel(7)^1 z = -100/7 \$
7	After cancelation	\$ z = -100/7 \$
8	Answer	D = \$ z = -100/7 \$

Steps

Problem

Solution

Solve

\$ 1/10 z - 9 = 3/5 z - 19\$

Move Variable terms to the left side and constant terms to the right side

\$ (z/10) + ((3z)/5) = -19 + 9 \$

Taking LCM as '\$10\$'

\$ (z + 6z)/10 = -10/1\$

By using cross multiplication

\$ z + 6z = -100\$

After Addition

\$ 7z = -100 \$

Dividing on both sides by '\$7\$' of the equality

\$ \cancel(7)^1/ \cancel(7)^1 z = -100/7 \$

After cancelation

\$ z = -100/7 \$

Answer

D = \$ z = -100/7 \$