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Step-2

Title: Solve the equation

Grade: 7-b Lesson: S2-L6

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

Steps	Problem	Solution
1	Solve	\$ 5/9 y - 6 = 1/3 y - 16 \$
2	Move variable terms to the left side and constant terms to the right side	\$ ((5y)/9) - ((y)/3) = -16 + 6 \$
3	Taking LCM as '\$9\$'	\$ (5y - 3y)/9 = -10/1\$
4	By using cross multiplication	\$ 5y - 3y = -90\$
5	After Subtraction	\$ 2y = -90 \$
6	Dividing on both sides by '\$2\$' of the equality	\$ \cancel(2)^1/ \cancel(2)^1 y = -\cancel90^(45)/\cancel2^1 \$
7	After cancelation	\$ y = - 45 \$
8	Answer	C = \$ y = - 45 \$

Steps

Problem

Solution

Solve

\$ 5/9 y - 6 = 1/3 y - 16 \$

Move variable terms to the left side and constant terms to the right side

\$ ((5y)/9) - ((y)/3) = -16 + 6 \$

Taking LCM as '\$9\$'

\$ (5y - 3y)/9 = -10/1\$

By using cross multiplication

\$ 5y - 3y = -90\$

After Subtraction

\$ 2y = -90 \$

Dividing on both sides by '\$2\$' of the equality

\$ \cancel(2)^1/ \cancel(2)^1 y = -\cancel90^(45)/\cancel2^1 \$

After cancelation

\$ y = - 45 \$

Answer

C = \$ y = - 45 \$