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Step-4

Title: Solve the equation

Grade: 7-b Lesson: S2-L3

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

Steps	Problem	Solution
1	Solve	\$ 2p + 12 = 0 \$
2	Adding '\$-12\$' on both sides	\$ 2p + \cancel12 - \cancel12 = 0 - 12 \$
3	After cancelation	\$ 2p = -12 \$
4	Dividing on both sides by '\$2\$' of the equality	\$ \cancel(2)^1/ \cancel(2)^1 p = \cancel(-12)^6/ \cancel(2)^1 \$
5	After cancelation we get	\$ p = - 6 \$
6	Answer	B = \$ p = - 6 \$

Steps

Problem

Solution

Solve

\$ 2p + 12 = 0 \$

Adding '\$-12\$' on both sides

\$ 2p + \cancel12 - \cancel12 = 0 - 12 \$

After cancelation

\$ 2p = -12 \$

Dividing on both sides by '\$2\$' of the equality

\$ \cancel(2)^1/ \cancel(2)^1 p = \cancel(-12)^6/ \cancel(2)^1 \$

After cancelation we get

\$ p = - 6 \$

Answer

B = \$ p = - 6 \$