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Step-2

Title: Solve the equation

Grade: 7-b Lesson: S2-L3

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

Steps	Problem	Solution
1	Solve	\$ 2x + 6 = 36 \$
2	Adding '\$-6\$' on both sides	\$ 2x + \cancel6 - \cancel6 = 36 - 6 \$
3	After cancelation	\$ 2x = 30 \$
4	Dividing on both sides by '\$2\$' of the equality	\$ \cancel(2)^1/ \cancel(2)^1 x = \cancel(30)^15/ \cancel(2)^1 \$
5	After cancelation	\$ x = 15 \$
6	Answer	C = \$ x = 15 \$

Steps

Problem

Solution

Solve

\$ 2x + 6 = 36 \$

Adding '\$-6\$' on both sides

\$ 2x + \cancel6 - \cancel6 = 36 - 6 \$

After cancelation

\$ 2x = 30 \$

Dividing on both sides by '\$2\$' of the equality

\$ \cancel(2)^1/ \cancel(2)^1 x = \cancel(30)^15/ \cancel(2)^1 \$

After cancelation

\$ x = 15 \$

Answer

C = \$ x = 15 \$