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Step-4

Title: Solve

Grade: 7-b Lesson: S1-L9

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

Steps	Problem	Solution
1	Solve	\$ 5(c+5) = 3c +20 \$
2	After Multiplication	\$ 5c + 25 = 3c +20 \$
3	Move variable term to the left side and constant term to the right side	\$ 5c-3c = 20-25 \$
4	After simplification	\$ 2c = -5 \$
5	Dividing on both sides by "\$2\$" of the equality	\$\cancel(2)^1/\cancel(2)^1 c = -5/2 \$
6	After simplification	\$ c = -5/2 \$
7	Answer	D = \$ c = -5/2 \$

Steps

Problem

Solution

Solve

\$ 5(c+5) = 3c +20 \$

After Multiplication

\$ 5c + 25 = 3c +20 \$

Move variable term to the left side and constant term to the right side

\$ 5c-3c = 20-25 \$

After simplification

\$ 2c = -5 \$

Dividing on both sides by "\$2\$" of the equality

\$\cancel(2)^1/\cancel(2)^1 c = -5/2 \$

After simplification

\$ c = -5/2 \$

Answer

D = \$ c = -5/2 \$