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Step-3

Title: Solve

Grade: 7-b Lesson: S1-L8

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

Steps	Problem	Solution
1	Solve	\$7k+9=4(k-3)\$
2	After simplification	\$ 7k + 9 = 4k - 12\$
3	Move "\$k\$" variable terms to the left side and constant terms to the right side	\$ 7k-4k = -12-9\$
4	After simplification	\$ 3k = -21\$
5	Dividing on both sides by '\$ 3 \$' of the equality	\$\cancel(3)/\cancel(3)k = \cancel(-21)^7/\cancel(3)^1\$
6	After cancellation	\$ k = -7\$
7	Answer	A = \$k= -7\$

Steps

Problem

Solution

Solve

\$7k+9=4(k-3)\$

After simplification

\$ 7k + 9 = 4k - 12\$

Move "\$k\$" variable terms to the left side and constant terms to the right side

\$ 7k-4k = -12-9\$

After simplification

\$ 3k = -21\$

Dividing on both sides by '\$ 3 \$' of the equality

\$\cancel(3)/\cancel(3)k = \cancel(-21)^7/\cancel(3)^1\$

After cancellation

\$ k = -7\$

Answer

A = \$k= -7\$