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Step-5

Title: Solve

Grade: 7-b Lesson: S1-L10

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

Steps	Problem	Solution
1	Solve	\$ 4g + 5/2 = 5(g/2 -6) \$
2	Taking LCM as '\$2\$' on both sides	\$ (8g + 5)/2 = 5((g -12)/2) \$
3	Canceling '\$2\$' in denominator on both sides	\$ (8g + 5)/\cancel(2) = 5((g -12)/\cancel(2)) \$
4	After Multiplication	\$8g + 5 = 5g - 60\$
5	Move Variable terms to left side Constant terms to right side	\$ 8g - 5g = -60 -5 \$ \$ 3g = -65 \$
6	Dividing on both sides by "\$3\$" of the equality	\$(\cancel(3)^1g)/\cancel(3)^1= (-65)/3 \$
7	After Cancellation	\$ g = (-65)/3 \$
8	Answer	A = \$ g = (-65)/3 \$

Steps

Problem

Solution

Solve

\$ 4g + 5/2 = 5(g/2 -6) \$

Taking LCM as '\$2\$' on both sides

\$ (8g + 5)/2 = 5((g -12)/2) \$

Canceling '\$2\$' in denominator on both sides

\$ (8g + 5)/\cancel(2) = 5((g -12)/\cancel(2)) \$

After Multiplication

\$8g + 5 = 5g - 60\$

Move Variable terms to left side Constant terms to right side

\$ 8g - 5g = -60 -5 \$

\$ 3g = -65 \$

Dividing on both sides by "\$3\$" of the equality

\$(\cancel(3)^1g)/\cancel(3)^1= (-65)/3 \$

After Cancellation

\$ g = (-65)/3 \$

Answer

A = \$ g = (-65)/3 \$