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Step-4

Title: Solve

Grade: 7-b Lesson: S1-L10

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

Steps	Problem	Solution
1	Solve	\$ 5(c/2+5) = (3c)/2 + 20 \$
2	Taking LCM as '\$2\$' on both sides	\$ 5((c+10)/2) = (3c + 40)/2 \$
3	Canceling '\$2\$' in denominator on both sides	\$ 5((c+10)/\cancel(2)) = (3c + 40)/\cancel(2) \$
4	After Multiplication	\$ 5(c+10) = (3c + 40) \$ \$ 5c + 50 = 3c + 40 \$
5	Move Variable terms to left side Constant terms to right side	\$ 5c - 3c = 40 - 50 \$ \$ 2c = -10 \$
6	Dividing on both sides by "\$2\$" of the equality	\$(\cancel(2)^1c)/\cancel(2)^1= \cancel(-10)^5/\cancel(2)^1 \$
7	After Cancellation	\$ c = -5 \$
8	Answer	D = \$ c = -5 \$

Steps

Problem

Solution

Solve

\$ 5(c/2+5) = (3c)/2 + 20 \$

Taking LCM as '\$2\$' on both sides

\$ 5((c+10)/2) = (3c + 40)/2 \$

Canceling '\$2\$' in denominator on both sides

\$ 5((c+10)/\cancel(2)) = (3c + 40)/\cancel(2) \$

After Multiplication

\$ 5(c+10) = (3c + 40) \$

\$ 5c + 50 = 3c + 40 \$

Move Variable terms to left side Constant terms to right side

\$ 5c - 3c = 40 - 50 \$

\$ 2c = -10 \$

Dividing on both sides by "\$2\$" of the equality

\$(\cancel(2)^1c)/\cancel(2)^1= \cancel(-10)^5/\cancel(2)^1 \$

After Cancellation

\$ c = -5 \$

Answer

D = \$ c = -5 \$