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Step-3

Title: Solve

Grade: 7-b Lesson: S1-L10

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

Steps	Problem	Solution
1	Solve	\$2/3(j-1/2) = 3/2(j+1/2)\$
2	Taking LCM as '\$2\$' on both sides	\$ 2/3((2j-1)/2) = 3/2((2j+1)/2) \$
3	Canceling '\$2\$' in denominator on both sides	\$ 2/3((2j-1)/\cancel(2)) = 3/2((2j+1)/\cancel(2)) \$
4	After Multiplication	\$ (4j-2)/3 = (6j+3)/2 \$
5	By cross Multiplication	\$ 2(4j-2) = 3(6j+3) \$ \$ 8j-4 = 18j+9 \$
6	Move Variable terms to left side Constant terms to right side	\$ 8j-18j = 9 + 4 \$ \$ -10j = 13 \$
7	Dividing on both sides by "\$-10\$" of the equality	\$(\cancel(-10)^1j)/\cancel(-10)^1= -13/10 \$
8	After Cancellation	\$ j = -13/10 \$
9	Answer	C = \$ j = -13/10 \$

Steps

Problem

Solution

Solve

\$2/3(j-1/2) = 3/2(j+1/2)\$

Taking LCM as '\$2\$' on both sides

\$ 2/3((2j-1)/2) = 3/2((2j+1)/2) \$

Canceling '\$2\$' in denominator on both sides

\$ 2/3((2j-1)/\cancel(2)) = 3/2((2j+1)/\cancel(2)) \$

After Multiplication

\$ (4j-2)/3 = (6j+3)/2 \$

By cross Multiplication

\$ 2(4j-2) = 3(6j+3) \$

\$ 8j-4 = 18j+9 \$

Move Variable terms to left side Constant terms to right side

\$ 8j-18j = 9 + 4 \$

\$ -10j = 13 \$

Dividing on both sides by "\$-10\$" of the equality

\$(\cancel(-10)^1j)/\cancel(-10)^1= -13/10 \$

After Cancellation

\$ j = -13/10 \$

Answer

C = \$ j = -13/10 \$