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Step-2

Title: Solve

Grade: 7-b Lesson: S1-L10

Explanation: Hello Students, time to practice and review the steps for the problem.

Lesson Steps

Steps	Problem	Solution
1	Solve	\$ 2(x-1/2) = 3(x+1/2)\$
2	Taking LCM as '\$2\$' on both sides	\$ 2((2x-1)/2) = 3((2x+1)/2) \$
3	Canceling '\$2\$' in denominator on both sides	\$ 2((2x-1)/\cancel(2)) = 3((2x+1)/\cancel(2)) \$
4	After Multiplication	\$ 4x - 2 = 6x + 3 \$
5	Move Variable terms to left side Constant terms to right side	\$ 4x - 6x = 3 + 2 \$ \$ -2x = 5 \$
6	Dividing on both sides by '\$-2\$' of the equality	\$ (\cancel(-2^1)x)/\cancel(-2)^1 = -5/2 \$
7	After Cancellation	\$ x = -5/2 \$
8	Answer	B = \$ x = -5/2 \$

Steps

Problem

Solution

Solve

\$ 2(x-1/2) = 3(x+1/2)\$

Taking LCM as '\$2\$' on both sides

\$ 2((2x-1)/2) = 3((2x+1)/2) \$

Canceling '\$2\$' in denominator on both sides

\$ 2((2x-1)/\cancel(2)) = 3((2x+1)/\cancel(2)) \$

After Multiplication

\$ 4x - 2 = 6x + 3 \$

Move Variable terms to left side Constant terms to right side

\$ 4x - 6x = 3 + 2 \$

\$ -2x = 5 \$

Dividing on both sides by '\$-2\$' of the equality

\$ (\cancel(-2^1)x)/\cancel(-2)^1 = -5/2 \$

After Cancellation

\$ x = -5/2 \$

Answer

B = \$ x = -5/2 \$